7 replies to this topic

[svdragster]

Hello,

I know there are many posts about this, but I don't understand a single word, so I hope someone can explain me some stuff.

I want a program to check if in the startup file exists a line with "shell.run". (Anything can be behind it)

How is that possible?

[Mads]

You would do something like this:

local f = io.open("/startup", "r") -- open the startup file for reading
local data = f:read("*a") -- read the entire file
f:close() -- close the file

if data:find("shell.run") then -- check if "shell.run" exists in the file contents.
    print("Found a line with shell.run!")
end

[svdragster]

Thanks ~_~

[Mads]

Btw, it has nothing to do with splitting strings

[svdragster]

xD Fail, well that's the only thing I found while searching for something like this...

[Kingdaro]

IIRC, :find() uses pattern matching, so you should probably escape that dot when looking for shell.run.

if data:find("shell%.run") then

[Mads]

Would be

if data:find("shell\.run") then

[Orwell]

mad, on 30 January 2013 - 08:27 AM, said:

Would be

if data:find("shell\.run") then

No, patterns in lua are escaped with a %. It's not the same as escaping strings. It's just indicating that the character (dot) is not a magic symbol, but just a plain dot.