8 replies to this topic

[darkmists]

i want to know if it is possible to put an if statement into a variable? if so how?

example of what i want to do

x = if i < 1 then
rs.setOutput("side", true)
end

[PixelToast]

rs.setOutput("side", i <1)

not sure what you want though

[Lyqyd]

No. Unless you're trying to use a function? What is the use case here, what are you actually trying to accomplish?

Edit:

PixelToast, on 06 April 2013 - 06:22 AM, said:

rs.setOutput("side", i <1)

not sure what you want though

This always sets the output, rather than only setting the output if i is less than one.

[Engineer]

You can use the ternary operator

local x = z==1 and 'its ture' or 'its false'

[PixelToast]

Lyqyd, on 06 April 2013 - 06:22 AM, said:

This always sets the output, rather than only setting the output if i is less than one.

.-.
rs.setOutput("side", i <1 or rs.getOutput("side"))
that better?

[darkmists]

nvm i figured it out while thinking of a way to explain. the code i want. very sorry about this. it was my stupid for forgetting how the code works.

[remiX]

rs.setOutput( "side", i < 1 and true or false )

[PixelToast]

remiX, on 06 April 2013 - 06:41 AM, said:

rs.setOutput( "side", i < 1 and true or false )

"and true"
dafuq?
"or false"
i dont even

seriously these do nothing .-.

[remiX]

Lol ternary operator... What do you mean it doesn't do anything? I thought just plain

rs.setOutput( 'back', i < 1 )

would work but...

Lyqyd, on 06 April 2013 - 06:22 AM, said:

PixelToast, on 06 April 2013 - 06:22 AM, said:

rs.setOutput("side", i <1) not sure what you want though

This always sets the output, rather than only setting the output if i is less than one.

EDIT:
Oh misunderstood lol, but setting it to false doesn't matter so rs.setOutput('side', i < 1) is fine really