7 replies to this topic

[Mackan90096]

Hi there! I'm wondering if you can make a script where it converts a input to another thing using this "factor":

Spoiler

local a = D
local b = E
local c = F
local d = G
local e = H
local f = I
local g = J
local h = K
local i = L
local j = M
local k = N
local l = O
local m = P
local n = Q
local o = R
local p = S
local q = T
local r = U
local s = V
local t = W
local u = X
local v = Y
local w = Z
local x = A
local y = B
local z = C
local a = D
local b = E
local c = F
local d = G
local e = H
local f = I
local g = J
local h = K
local i = L
local j = M
local k = N
local l = O
local m = P
local n = Q
local o = R
local p = S
local q = T
local r = U
local s = V
local t = W
local u = X
local v = Y
local w = Z
local x = A
local y = B
local z = C

local A = d
local B = e
local C = f
local D = g
local E = h
local F = i
local G = j
local H = k
local I = l
local J = m
local K = n
local L = o
local M = p
local N = q
local O = r
local P = s
local Q = t
local R = u
local S = v
local T = w
local U = x
local V = y
local W = z
local X = a
local Y = b
local Z = c

So for example, "Hi" would be kL

If you can, how?

[theoriginalbit]

Ok its a nice and small program that I wrote up in a few seconds, so I don't feel code monkey like, so... done and commented...
http://pastebin.com/HddiLkwG

EDIT: Oh and btw, its not really an 'encryption' its an encoding. There is no key involved, it doesn't convert every character, and it preserves formatting (which would be fixed by the last point) so it cannot be classed as an encryption.

Edited by theoriginalbit, 24 April 2013 - 01:40 AM.

[remiX]

They need to be in " " btw

But don't use this, it isn't secure at all...
Something like this would be better

[theoriginalbit]

remiX, on 24 April 2013 - 01:40 AM, said:

Something like this would be better

Well it depends on if when OP says they wants an 'encryption' whether they actually do, or whether a hash could fill the requirements.

[Mackan90096]

Is there a decryption using this too?

[remiX]

Mackan90096, on 24 April 2013 - 03:04 AM, said:

Is there a decryption using this too?

Yes, this would be the decryption function.

function decrypt(str)
	local temp = ""
	for i = 1, str:len() do
		local char = str:sub(i,i)
		for i, v in pairs(lookup) do
			if v == char then temp = temp .. char break end
		end
	end
	return str
end

Untested

[Dlcruz129]

Mackan90096, on 24 April 2013 - 03:04 AM, said:

Is there a decryption using this too?

You could just swap the table values. Instead of ["a"] = "e"...
You can do
["e"] = "a"

[theoriginalbit]

Dlcruz129, on 24 April 2013 - 03:12 AM, said:

You could just swap the table values. Instead of ["a"] = "e"...
You can do
["e"] = "a"

That would cause problems with initial lookup, unless you had a separate lookup table... personally I would use the function remiX posted (that btw doesn't work), with some changes.

function decode(str)
  -- create our return string
  local temp = ""
  -- loop through the input string
  for i = 1, #str do
	-- make a variable to track if a match was found (this is for non-alphabetic character support)
	local found = false
	-- get the current character
	local char = str:sub(i,i)
	-- loop through all the table entries
	for k, v in pairs(lookup) do
	  -- if the entry in the table is the same as the current character
	  if v == char then
		-- append it to the return value
		temp = temp..k
		-- set the found flag to true
		found = true
		-- stop searching the lookup table
		break
	  end
	end
	-- if we didn't find a match, it's not an alphabetic character, so append it
	if not found then
	  temp = temp..char
	end
  end
  -- return the decoded string
  return temp
end