6 replies to this topic

[KingofGamesYami]

table = {"A", "B", "C")

Is there any way I can convert this to

tString = "ABC"

Without knowing how many variables I have stored?

Question was answered here : http://stackoverflow...bles-in-a-table

Edited by KingofGamesYami, 18 April 2014 - 07:08 AM.

[Wojbie]

You want to use table.concat() for that. for more info about that function see here.

Edited by wojbie, 18 April 2014 - 07:08 AM.

[KingofGamesYami]

wojbie, on 18 April 2014 - 07:08 AM, said:

You want to use table.concat() for that. for more info about that function see here.

I ninja'd you while editing my main post... LOL

[Dog]

EDIT: Ninja'd

Yes. You would use #table to find the number of variables stored. For example:

for i = 1,#table do

Then you would use the double dot/period ( .. ) to concatenate each one onto the other like so

newString = newString .. table[i]

If you need a more explicit example let me know. One other thing - it's not a good idea to name your table "table" - especially if you don't localize the variable name 'table'

Edited by Dog, 18 April 2014 - 07:09 AM.

[theoriginalbit]

do note however that table.concat only works on indexed tables, ergo any values stored under a key will not appear in the resultant string.

[KingofGamesYami]

Dog, on 18 April 2014 - 07:09 AM, said:

EDIT: Ninja'd

Yes. You would use #table to find the number of variables stored. For example:

for i = 1,#table do

Then you would use the double dot/period ( .. ) to concatenate each one onto the other like so

newString = newString .. table[i]

If you need a more explicit example let me know. One other thing - it's not a good idea to name your table "table" - especially if you don't localize the variable name 'table'

Yeah, I know. That was an example. My actual code is long and mostly irrelevant (making a virtual keyboard on screen )

theoriginalbit, on 18 April 2014 - 07:11 AM, said:

do note however that table.concat only works on indexed tables, ergo any values stored under a key will not appear in the resultant string.

I assumed it would... How would it know which comes first otherwise? Not a problem in this case.

[apemanzilla]

If for some reason you have non-number indices, you'd need to loop through the table with the "pairs" function:

local tbl = {}
tbl[1] = "a"
tbl["a"] = "b"
local str = ""
for _,v in pairs(tbl) do
  str = str..v
end

Please note however the order may not be preserved when this method is used.