9 replies to this topic

[lare290]

How to get variable from turtle.getSelectedSlot()?

[MKlegoman357]

Just like you catch variables returned by any Lua function:

local slot = turtle.getSelectedSlot()

[lare290]

It just says "bios:366: [string "turtlebutler"]:8: unexcepted symbol"
What am I doing wrong now?

local slot = turtle.getSelectedSlot()
write ("Do sir want some drinks? ")
variable = read()
if variable == ("yes") then
if turtle.getItemCount(turtle.getSelectedSlot())>0 then
turtle.drop()
else
turtle.select(local slot+1) then
turtle.drop()
end
elseif variable == ("no") then
print ("Very well")
end

I just try to get it use next inventory slot when current one is empty

Edited by lare290, 13 December 2014 - 12:15 PM.

[ebernerd]

When you declare a local variable, you use the word local.

When you're using said variable, do not attach local to it. So you're code for that would be

turtle.select(slot+1)

Edited by Pseudonymous, 13 December 2014 - 12:29 PM.

[theoriginalbit]

merged threads. it is best to keep code related to the same program in the same thread for better and more accurate assistance.

[lare290]

Pseudonymous, on 13 December 2014 - 12:27 PM, said:

When you declare a local variable, you use the word local.

When you're using said variable, do not attach local to it. So you're code for that would be

turtle.select(slot+1)

I did it like that, still same error

Edited by lare290, 13 December 2014 - 12:46 PM.

[ebernerd]

lare290, on 13 December 2014 - 12:29 PM, said:

Pseudonymous, on 13 December 2014 - 12:27 PM, said:

When you declare a local variable, you use the word local.

When you're using said variable, do not attach local to it. So you're code for that would be

turtle.select(slot+1)

I did it like that, still same error

I just realized, you have a then attached on to the end of that line. You can't have that there.
I'll rewrite your code:

local slot = turtle.getSelectedSlot()
write("Does sir want some drink?")
local variable = read() --#I suggest using a different variable name
if variable == "Yes" then
  if turtle.getItemCount(turtle.getSelectedSlot))>0 then
	turtle.drop()
  else
	turtle.select(slot + 1)
	turtle.drop()
  end
elseif variable == "no" then
  print("Very well.")
end

Edited by Pseudonymous, 13 December 2014 - 12:52 PM.

[lare290]

Why it needs local for drinks-variable? It works right without it

[KingofGamesYami]

lare290, on 13 December 2014 - 01:10 PM, said:

Why it needs local for drinks-variable? It works right without it

Generally, you always want to define your variables locally. They are accessed faster and other programs cannot mess with them. Your program will work with global variables, but it is bad practice to do so and will probably give you problems when you get into more advanced programs.

[The_Cat]

Hi, i have seen your code and i rewrote it in a way that will check each slot, and if it doesnt find any drinks it tells you. Reads the comments i put with it.

function checkForDrinks() --#Function to check if any of the slots have any items in it
for i = 1,16 do --#For Loop
  turtle.select(i)
  if i == 16 then --#When then for loop reaches 16 it will go in to this if statement
   if turtle.getItemCount() == 0 then --#Then it will see if the item count is equal to 0 if so it will break out of loop
	print("No drinks in Inventory.")
   end
  end
  if turtle.getItemCount(turtle.getSelectedSlot())>0 then -- You wrote this
   turtle.drop()
   print("Here you go sir.")
   break --#Break means that it will break out of the loop as soon as it has enterd this if statement
  end
end
end
write ("Do sir want some drinks? ")
variable = read()
if variable == ("yes") then
checkForDrinks() --#Put the function here so when the variable is read as yes it will run it
elseif variable == ("no") then
print ("Very well")
end

Edited by The_Cat, 13 December 2014 - 03:05 PM.