6 replies to this topic

[xxx]

I'm trying to make a program which when run will send 3 pulses of white color redstone output through a bundled cable.
I haven't coded Lua in a long time, so this should be easy for you guys, but I can't figure it out myself, nor with Google.

Thanks for all help!


My code:

rs.setBundledOutput("back", color.white)
os.sleep(1)
rs.setBundledOutput("back", color.white)
os.sleep(1)
rs.setBundledOutput("back", color.white)
os.sleep(1)
shell.run("clear")
end

[KaoS]

close, you just need to clear the output between pulses

rs.setBundledOutput("back", color.white)
os.sleep(0.5)
rs.setBundledOutput("back",0)
os.sleep(0.5)
rs.setBundledOutput("back", color.white)
os.sleep(0.5)
rs.setBundledOutput("back",0)
os.sleep(0.5)
rs.setBundledOutput("back", color.white)
os.sleep(0.5)
rs.setBundledOutput("back",0)

and the end is unneeded

[xxx]

Thank you for the quick help!

I did exactly what you wrote, but i do only get "attempt to index ? (a nil value).

[Luanub]

It's colors.white, plural colors not color.

[KaoS]

sorry lol, I was just copying and adapting it... made a blind mistake, corrected again

rs.setBundledOutput("back", colors.white)
sleep(0.5)
rs.setBundledOutput("back",0)
sleep(0.5)
rs.setBundledOutput("back", colors.white)
sleep(0.5)
rs.setBundledOutput("back",0)
sleep(0.5)
rs.setBundledOutput("back", colors.white)
sleep(0.5)
rs.setBundledOutput("back",0)

luanub, on 16 August 2012 - 07:24 AM, said:

It's colors.white, plural colors not color.

yep, beat me to it

[xxx]

Thank you, it works!

[Pharap]

To condense it do:

for cnt = 1,3 do
rs.setBundledOutput("back", colors.white)
sleep(0.5)
rs.setBundledOutput("back",0)
sleep(0.5)
end

A for loop (for varaible = startnumber,endnumber do end)
will go through the stuff in it with the set variable going up one each time.
Useful for doing something a set number of times or doing something for a multitude of numbers.