ComputerCraft | Programmable Computers for Minecraft

if accountMenu == true and loggedBalance == false and loggedSettings == false and balanceWithdraw == false or balanceDeposit == false then

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Hello.

I'm trying to make a program that splits a string up at "&pwd=" but i've looked at the Lua manual, but no such luck there...

current code:

test = string.gmatch(msg, "(%w+)&pwd=(%w+)")
print(tostring(test))

"msg" :

msg = "$usr=64a36e9c9c4d278b9d774dc234cfd0b5572c96e3e6dc6978d86781a671e20ce2&pwd=64a36e9c9c4d278b9d774dc234cfd0b5572c96e3e6dc6978d86781a671e20ce2"
---------^--------------------------------------------------------------------^^ the &pwd= has to be the "splitter", so i can return 2 variables with the $usr=........   and the &pwd=........

The output is:

function: 963d9a

If anyone are able to help me then please tell me

local _, _, first, second = string.find(msg, "^(%w+)&pwd=(%w+)$")

LBPHacker, on 31 August 2013 - 07:19 AM, said:

local _, _, first, second = string.find(msg, "^(%w+)&pwd=(%w+)$")

local first, second = string.match(msg, "(%w+)&pwd=(%w+)")

floppyjack, on 31 August 2013 - 07:25 AM, said:

function isPermitted(name, pass)
	local failRead = fs.open(".accounts", "r")
	local failRd = failRead.readAll()
	failRead.close()
	if not string.find(failRd, "failSafe") then
		local failSafe = fs.open(".accounts", "a")
		failSafe.writeLine("failsafe")
		failSafe.close()
	end	

	local rRead = fs.open(".accounts", "r")
	local rAll = rRead.readAll()
	rRead.close()
	print(tostring(rAll))
	if string.find(rAll, "&usr="..name.."&pwd="..pass) then
		return true
	else
		return false
	end
end	

if string.find(rAll, "&usr="..name.."&pwd="..pass) then

local _, _, user, pass = string.find(msg, "^(%w+)&pwd=(%w+)*")

local _, _, user, pass = string.find(msg, "(%w+)&pwd=(%w+)")

local _, _, user, pass = string.find(msg, "^(%w+)&pwd=(%w+)$")