using string.match with a table (variables)
gfcwfzkm 26 Feb 2014
Hi CC_Forum,
im trying to find a 'word' in a variable and i want to use table(s) cause there are many of these 'words'. But my Problem is, that it does nothing
Maybe its cause i still got some problems with for-loops and string.match()
(Here my Complete Code)
http://pastebin.com/paC8kRRx
What could be the solution for this?
Thanks for the Help
gfcwfzkm (Pascal)
im trying to find a 'word' in a variable and i want to use table(s) cause there are many of these 'words'. But my Problem is, that it does nothing
Maybe its cause i still got some problems with for-loops and string.match()
for ii,xx in pairs(badNPC) do if string.match(Str,ii) == true then term.setTextColor(colors.blue) return true end endI want that it change the Textcolor if the variable 'Str' is in the table 'badNPC'. But well, it dont works good :/
(Here my Complete Code)
http://pastebin.com/paC8kRRx
What could be the solution for this?
Thanks for the Help
gfcwfzkm (Pascal)
Engineer 26 Feb 2014
For this particular issue, I would just use the standard compare operator: ==
So, the function would look like this:
So, the function would look like this:
New function
gfcwfzkm 26 Feb 2014
I cant use == cause the variable contains behind some numbers (from the NPCs). Now i changed string.match(Str,ii) to string.match(Str,xx) but it still dont wanna work :/
CometWolf 26 Feb 2014
String.match dosen't return true, it returns the matched string, so this would always be false
Edited by CometWolf, 26 February 2014 - 10:22 PM.
if string.match(Str,ii) == true thenJust drop the "== true", this way it will perform the if block aslong as the result of string.match is not nil or false.
if string.match(Str,ii) then
Edited by CometWolf, 26 February 2014 - 10:22 PM.