Bit.bxor - Revision history

Watcher7: Changed nonexistent type int to type number.

2013-07-12T01:21:30Z

Changed nonexistent type int to type number.

2013-04-22T14:16:17Z

Use type template

2012-11-30T18:27:29Z

Mapped "int" to "int (type)".

2012-11-28T18:28:49Z

Moved to CAT:APIFunctions

2012-03-11T22:54:34Z

Rewrite

2012-02-28T10:39:00Z

2012-02-27T01:41:18Z

2012-02-27T00:17:06Z

‎Explanation

2012-02-27T00:14:48Z

‎Above 1 and Below 0

2012-02-26T23:59:44Z

‎Above 1 and Below 0

@@ Line 2: / Line 2: @@
 {{Function
 |name=bit.bxor
-|args={{Type|int}} m, {{Type|int}} n
+|args={{Type|number}} m, {{Type|number}} n
 |api=bit
-|returns={{Type|int}} the value of <var>m</var> XOR <var>n</var>
+|returns={{Type|number}} the value of <var>m</var> XOR <var>n</var>
 |addon=ComputerCraft
 |desc=Computes the bitwise exclusive OR of two numbers

@@ Line 2: / Line 2: @@
 {{Function
 |name=bit.bxor
-|args=[[int (type)|int]] m, [[int (type)|int]] n
+|args={{Type|int}} m, {{Type|int}} n
 |api=bit
-|returns=[[int (type)|int]] the value of <var>m</var> XOR <var>n</var>
+|returns={{Type|int}} the value of <var>m</var> XOR <var>n</var>
 |addon=ComputerCraft
 |desc=Computes the bitwise exclusive OR of two numbers

@@ Line 4: / Line 4: @@
 |args=[[int (type)|int]] m, [[int (type)|int]] n
 |api=bit
-|returns=[[int]] the value of <var>m</var> XOR <var>n</var>
+|returns=[[int (type)|int]] the value of <var>m</var> XOR <var>n</var>
 |addon=ComputerCraft
 |desc=Computes the bitwise exclusive OR of two numbers

@@ Line 1: / Line 1: @@
-== Explanation ==
+{{lowercase}}
-All bit operations operate in Binary numeral system [http://en.wikipedia.org/wiki/Binary_numeral_system].
+{{Function
-So if you understand the basics than XOR is an EXCLUSIVE OR and like an OR with exclusion give:
+== Explanation ==
-----
+All bit operations operate in binary numeral system [http://en.wikipedia.org/wiki/Binary_numeral_system]. An exclusive OR operation between two bits yields a 1 if the bits are unequal and a 0 if they are equal. This function produces an output by computing the XOR of each bit of its two inputs independently. So, for the example above:
-01001011 (75)
-----
-<i>XOR</i>
-----
-00011000 (24)
-----
-<i>=</i>
-----
-01010011 (83)
-----
-Bits are XOR`red sequentially.
+{| class="wikitable"

← Older revision		Revision as of 01:41, 27 February 2012
Line 5:		Line 5:
	== Above 1 and Below 0 ==		== Above 1 and Below 0 ==
	I tried to research and work on numbers above 1, but it gets kind of confusing, at first it is simple(ex. (1,2)=3; (2,2)=0; (4,2)=6; (5,2)=7;), but then when you input (6,2) it equals 4. I tried working on this for half and hour with no luck. When I tried to work on numbers below 0 at first it was as confusing as above 1 and as simple as 0 and 1, but still a positive number. Then when I mixed negative and positive, I got 4294967295 from (-1,1). I didn't try to research it. So hopefully someone will edit this and explain how going above 1 works, and possibly include an equation or 2.		I tried to research and work on numbers above 1, but it gets kind of confusing, at first it is simple(ex. (1,2)=3; (2,2)=0; (4,2)=6; (5,2)=7;), but then when you input (6,2) it equals 4. I tried working on this for half and hour with no luck. When I tried to work on numbers below 0 at first it was as confusing as above 1 and as simple as 0 and 1, but still a positive number. Then when I mixed negative and positive, I got 4294967295 from (-1,1). I didn't try to research it. So hopefully someone will edit this and explain how going above 1 works, and possibly include an equation or 2.
−
−	~~--[[User:Zach1231\|Zach1231]] 23:59, 26 February 2012 (UTC)~~

@@ Line 1: / Line 1: @@
 == Explanation ==
 ''XOR'' is similar to the ''OR'' gate, but the numbers can '''not''' be equal.
-(ex. 0<u>V</u>0=0; 1<u>V</u>0=1; 0<u>V</u>1=1; 1<u>V</u>1=0)
+(ex. (0,0)=0; (1,0)=1; (0,1)=1; (1,1)=0)
 == Above 1 and Below 0 ==

← Older revision		Revision as of 00:14, 27 February 2012
Line 6:		Line 6:
	I tried to research and work on numbers above 1, but it gets kind of confusing, at first it is simple(ex. (1,2)=3; (2,2)=0; (4,2)=6; (5,2)=7;), but then when you input (6,2) it equals 4. I tried working on this for half and hour with no luck. When I tried to work on numbers below 0 at first it was as confusing as above 1 and as simple as 0 and 1, but still a positive number. Then when I mixed negative and positive, I got 4294967295 from (-1,1). I didn't try to research it. So hopefully someone will edit this and explain how going above 1 works, and possibly include an equation or 2.		I tried to research and work on numbers above 1, but it gets kind of confusing, at first it is simple(ex. (1,2)=3; (2,2)=0; (4,2)=6; (5,2)=7;), but then when you input (6,2) it equals 4. I tried working on this for half and hour with no luck. When I tried to work on numbers below 0 at first it was as confusing as above 1 and as simple as 0 and 1, but still a positive number. Then when I mixed negative and positive, I got 4294967295 from (-1,1). I didn't try to research it. So hopefully someone will edit this and explain how going above 1 works, and possibly include an equation or 2.

−	--[[User:Zach1231\|Zach1231]] 23:59, 26 February 2012 (UTC) ~~Zach1231~~	+	--[[User:Zach1231\|Zach1231]] 23:59, 26 February 2012 (UTC)

← Older revision		Revision as of 23:59, 26 February 2012
Line 6:		Line 6:
	I tried to research and work on numbers above 1, but it gets kind of confusing, at first it is simple(ex. (1,2)=3; (2,2)=0; (4,2)=6; (5,2)=7;), but then when you input (6,2) it equals 4. I tried working on this for half and hour with no luck. When I tried to work on numbers below 0 at first it was as confusing as above 1 and as simple as 0 and 1, but still a positive number. Then when I mixed negative and positive, I got 4294967295 from (-1,1). I didn't try to research it. So hopefully someone will edit this and explain how going above 1 works, and possibly include an equation or 2.		I tried to research and work on numbers above 1, but it gets kind of confusing, at first it is simple(ex. (1,2)=3; (2,2)=0; (4,2)=6; (5,2)=7;), but then when you input (6,2) it equals 4. I tried working on this for half and hour with no luck. When I tried to work on numbers below 0 at first it was as confusing as above 1 and as simple as 0 and 1, but still a positive number. Then when I mixed negative and positive, I got 4294967295 from (-1,1). I didn't try to research it. So hopefully someone will edit this and explain how going above 1 works, and possibly include an equation or 2.

−	--[[~~Special~~:~~Contributions/68.46.223.42~~\|~~68.46.223.42~~]] 23:56, 26 February 2012 (UTC) Zach1231	+	--[[User:Zach1231\|Zach1231]] 23:59, 26 February 2012 (UTC) Zach1231